Exam 200-301 | Question id=5513 | Network Fundamentals |
Which is the valid broadcast ID for the IP address 192.24.134.12 with a subnet mask of 255.255.255.128?
A. |
192.24.134.127 | |
B. |
192.24.134.128 | |
C. |
192.24.134.129 | |
D. |
192.24.134.131 |
192.24.134.127 is the valid broadcast ID for the IP address 192.24.134.12 with a subnet mask of 255.255.255.128.
The valid range for the IP address 192.24.134.12 with a subnet mask of 255.255.255.128 is 192.24.134.1 - 192.24.134.126. The subnet ID is 192.24.134.0.
Subnetting allows you to split single and large subnets defined by Class A, B, and C IP addresses into multiple subnets with smaller IP address host ranges. Subnetting allows efficient use of IP addressing space, which has become a scarce resource.
To subnet an existing network, you will use host bits to split the IP address into multiple logical subnets. For example, if you use three bits of the host ID for subnetting, you have created 23 = 2 x 2 x 2 = 8 subnets. Remaining bits of the host ID in decimal form will form the number of hosts on each subnet.
All other options are incorrect as these IP addresses fall in other subnets.