| Exam 200-301 | Question id=5494 | IP Connectivity |
Router 5 has four interfaces. The networks hosted on each interface are as follows:
Fa0/1 192.168.5.4/29
Fa0/2 192.168.6.0/24
Fa0/3 192.168.7.0/24
S0/0 172.16.5.0/24
You execute the following commands on the router:
Router5(config)# router bgp 20
Router5(config-router)# network 192.168.5.0
Router5(config-router)# network 192.168.6.0
Router5(config-router)# network 192.168.7.0
Router5(config-router)# network 172.16.5.0
Router5(config-router)# neighbor 172.16.5.2 remote-as 50
Router5(config-router)# aggregate-address 192.168.5.0 255.255.252.0
After this command sequence is executed, what routes will be present in the routing table of the router at 172.16.5.2?
| A. |
192.168.5.4/29 | |
| B. |
172.16.5.0/24 | |
| C. |
192.168.6.0/24 | |
| D. |
192.168.7.0/24 | |
| E. |
none of these will be present | |
| F. |
only network addresses beginning with 192 will be present |
Despite the inclusion of the command aggregate-address 192.168.5.0 255.255.252.0, all subnets of the aggregate route will also be placed in the routing updates because of the omission of the summary-only keyword. Therefore, 192.168.5.4/29, 172.16.5.0/16, 192.168.6.0/24 and 192.168.7.0/24 will be present.
Had the following command been executed, the subnet addresses would not appear in the routing table of the router at 172.16.5.2:
Router5(config-router)# aggregate-address 192.168.5.0 255.255.252.0 summary-only
Therefore, both the aggregate address and all of the 192.168.0.0 subnets will be in the routing table.
The 172.16.5.0/24 network will be in the routing table of the router at 172.160.5.1 because it is directly connected.